What are the solutions to the equation 6x^2+28x-2=2x-10 ?

The solutions to the equation 6x^2+28x-2=2x-10 are x=-1/3 ,x=-4

Find the zeros of 6x^2+28x-2=2x-10

The zeros of 6x^2+28x-2=2x-10 are x=-1/3 ,x=-4

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6 x^{2} + 28 x - 2 = 2 x - 10

x = - \frac{1}{3}, x = - 4

Decimal Notation

x = - 0.33333 \dots, x = - 4

Solution steps

6 x^{2} + 28 x - 2 = 2 x - 10

Move

10

to the left side

6 x^{2} + 28 x + 8 = 2 x

Move

2 x

to the left side

6 x^{2} + 26 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 6 \cdot 8}{2 \cdot 6}

2 6^{2} - 4 \cdot 6 \cdot 8 = 22

x_{1, 2} = \frac{- 26 \pm 22}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 26 + 22}{2 \cdot 6}, x_{2} = \frac{- 26 - 22}{2 \cdot 6}

x = \frac{- 26 + 22}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 26 - 22}{2 \cdot 6} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 4

x^{2} - 13 = - 4

x^{2} - 6 x + 34 = 0

x^{2} - 10 x + 9 = 10

- 16 x^{2} + 29 x - 12 = 0

- 5 x + 200 = 0.5 x^{2} + 100

What are the solutions to the equation 6x^2+28x-2=2x-10 ?
The solutions to the equation 6x^2+28x-2=2x-10 are x=-1/3 ,x=-4
Find the zeros of 6x^2+28x-2=2x-10
The zeros of 6x^2+28x-2=2x-10 are x=-1/3 ,x=-4