What are the solutions to the equation -16t^2+64t=0 ?

The solutions to the equation -16t^2+64t=0 are t=0,t=4

Find the zeros of -16t^2+64t=0

The zeros of -16t^2+64t=0 are t=0,t=4

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- 16 t^{2} + 64 t = 0

t = 0, t = 4

Solution steps

- 16 t^{2} + 64 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 0 = 64

t_{1, 2} = \frac{- 64 \pm 64}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 64 + 64}{2 ( - 16 )}, t_{2} = \frac{- 64 - 64}{2 ( - 16 )}

t = \frac{- 64 + 64}{2 ( - 16 )} : 0

t = \frac{- 64 - 64}{2 ( - 16 )} : 4

The solutions to the quadratic equation are:

t = 0, t = 4

(- 4)^{7}

\frac{6}{5} x + \frac{7}{10} = x - \frac{3}{2}

(- 2 x + \frac{1}{3})^{2} > 0

6 x = 16

5 x < 16 + x

What are the solutions to the equation -16t^2+64t=0 ?
The solutions to the equation -16t^2+64t=0 are t=0,t=4
Find the zeros of -16t^2+64t=0
The zeros of -16t^2+64t=0 are t=0,t=4