What are the solutions to the equation (6y-2)(y-2)=136 ?

The solutions to the equation (6y-2)(y-2)=136 are y=6,y=-11/3

Find the zeros of (6y-2)(y-2)=136

The zeros of (6y-2)(y-2)=136 are y=6,y=-11/3

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(6 y - 2) (y - 2) = 136

y = 6, y = - \frac{11}{3}

Decimal Notation

y = 6, y = - 3.66666 \dots

Solution steps

(6 y - 2) (y - 2) = 136

Expand

(6 y - 2) (y - 2) : 6 y^{2} - 14 y + 4

6 y^{2} - 14 y + 4 = 136

Move

136

to the left side

6 y^{2} - 14 y - 132 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 6 ( - 132 )}{2 \cdot 6}

(- 14)^{2} - 4 \cdot 6 (- 132) = 58

y_{1, 2} = \frac{- ( - 14 ) \pm 58}{2 \cdot 6}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 58}{2 \cdot 6}, y_{2} = \frac{- ( - 14 ) - 58}{2 \cdot 6}

y = \frac{- ( - 14 ) + 58}{2 \cdot 6} : 6

y = \frac{- ( - 14 ) - 58}{2 \cdot 6} : - \frac{11}{3}

The solutions to the quadratic equation are:

y = 6, y = - \frac{11}{3}

3 x^{2} - 8 x - 1 = - 6 x + 4

x, y = f^{2} (x + 1)^{2}

20 = 100 - 4.9 t^{2}

d (4 d + 5) - 8 = 0

9 x = - 4 x^{2} - 5

What are the solutions to the equation (6y-2)(y-2)=136 ?
The solutions to the equation (6y-2)(y-2)=136 are y=6,y=-11/3
Find the zeros of (6y-2)(y-2)=136
The zeros of (6y-2)(y-2)=136 are y=6,y=-11/3