What are the solutions to the equation completesquare 2x^2-14x+10=26 ?

The solutions to the equation completesquare 2x^2-14x+10=26 are x=8,x=-1

Find the zeros of completesquare 2x^2-14x+10=26

The zeros of completesquare 2x^2-14x+10=26 are x=8,x=-1

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2 x^{2} - 14 x + 10 = 26

x = 8, x = - 1

Solution steps

2 x^{2} - 14 x + 10 = 26

Move

10

to the right side

2 x^{2} - 14 x = 16

Divide both sides by

2

\frac{2 x ^{2} - 14 x}{2} = \frac{16}{2}

x^{2} - 7 x = 8

Rewrite in the form

(x + a)^{2} = b

(x - \frac{7}{2})^{2} = \frac{81}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{7}{2} = \frac{81}{4} : x = 8

Solve

x - \frac{7}{2} = - \frac{81}{4} : x = - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

x^{2} - 14 x + 35 = - 10

v, E = m g h + \frac{1}{2} m v^{2}

x, x (y^{2} + 3) = (y^{2} x^{2}) + 3

2 x^{2} + 9 x + 10 = 0

15 x^{2} - 16 x + 4 = 0

What are the solutions to the equation completesquare 2x^2-14x+10=26 ?
The solutions to the equation completesquare 2x^2-14x+10=26 are x=8,x=-1
Find the zeros of completesquare 2x^2-14x+10=26
The zeros of completesquare 2x^2-14x+10=26 are x=8,x=-1