What are the solutions to the equation 0.03x^2+35x-712=0 ?

The solutions to the equation 0.03x^2+35x-712=0 are x=20,x=-3560/3

Find the zeros of 0.03x^2+35x-712=0

The zeros of 0.03x^2+35x-712=0 are x=20,x=-3560/3

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0.03 x^{2} + 35 x - 712 = 0

x = 20, x = - \frac{3560}{3}

Decimal Notation

x = 20, x = - 1186.66666 \dots

Solution steps

0.03 x^{2} + 35 x - 712 = 0

Multiply both sides by

100

3 x^{2} + 3500 x - 71200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3500 \pm 350 0 ^{2} - 4 \cdot 3 ( - 71200 )}{2 \cdot 3}

350 0^{2} - 4 \cdot 3 (- 71200) = 3620

x_{1, 2} = \frac{- 3500 \pm 3620}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3500 + 3620}{2 \cdot 3}, x_{2} = \frac{- 3500 - 3620}{2 \cdot 3}

x = \frac{- 3500 + 3620}{2 \cdot 3} : 20

x = \frac{- 3500 - 3620}{2 \cdot 3} : - \frac{3560}{3}

The solutions to the quadratic equation are:

x = 20, x = - \frac{3560}{3}

m^{2} + 3 m - 8 = 2

r^{2} = (93)^{2} + (27)^{2}

5 - 4 x - x^{2} = 0

x (x + 4) = 21

7 x^{2} - 19 = 0

What are the solutions to the equation 0.03x^2+35x-712=0 ?
The solutions to the equation 0.03x^2+35x-712=0 are x=20,x=-3560/3
Find the zeros of 0.03x^2+35x-712=0
The zeros of 0.03x^2+35x-712=0 are x=20,x=-3560/3