What are the solutions to the equation 2p^2-5p-2=-3p^2 ?

The solutions to the equation 2p^2-5p-2=-3p^2 are p=(5+sqrt(65))/(10),p=(5-sqrt(65))/(10)

Find the zeros of 2p^2-5p-2=-3p^2

The zeros of 2p^2-5p-2=-3p^2 are p=(5+sqrt(65))/(10),p=(5-sqrt(65))/(10)

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2 p^{2} - 5 p - 2 = - 3 p^{2}

p = \frac{5 + 65}{10}, p = \frac{5 - 65}{10}

Decimal Notation

p = 1.30622 \dots, p = - 0.30622 \dots

Solution steps

2 p^{2} - 5 p - 2 = - 3 p^{2}

Move

3 p^{2}

to the left side

5 p^{2} - 5 p - 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 2) = 65

p_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 65}{2 \cdot 5}, p_{2} = \frac{- ( - 5 ) - 65}{2 \cdot 5}

p = \frac{- ( - 5 ) + 65}{2 \cdot 5} : \frac{5 + 65}{10}

p = \frac{- ( - 5 ) - 65}{2 \cdot 5} : \frac{5 - 65}{10}

The solutions to the quadratic equation are:

p = \frac{5 + 65}{10}, p = \frac{5 - 65}{10}

\frac{x ^{2}}{3} - \frac{3 x}{4} = \frac{1 - x}{6}

1653.75 = 1500 (1 + 2 x + x^{2})

x, x^{2} + 5 y^{2} + e^{2 y} = 5

(x + 4)^{2} - 5 = 0

(x - 8)^{2} = 10

What are the solutions to the equation 2p^2-5p-2=-3p^2 ?
The solutions to the equation 2p^2-5p-2=-3p^2 are p=(5+sqrt(65))/(10),p=(5-sqrt(65))/(10)
Find the zeros of 2p^2-5p-2=-3p^2
The zeros of 2p^2-5p-2=-3p^2 are p=(5+sqrt(65))/(10),p=(5-sqrt(65))/(10)