What are the solutions to the equation factor 8x^2+10x-7=0 ?

The solutions to the equation factor 8x^2+10x-7=0 are x= 1/2 ,x=-7/4

Find the zeros of factor 8x^2+10x-7=0

The zeros of factor 8x^2+10x-7=0 are x= 1/2 ,x=-7/4

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8 x^{2} + 10 x - 7 = 0

x = \frac{1}{2}, x = - \frac{7}{4}

Decimal Notation

x = 0.5, x = - 1.75

Solution steps

8 x^{2} + 10 x - 7 = 0

Factor

8 x^{2} + 10 x - 7 : (2 x - 1) (4 x + 7)

(2 x - 1) (4 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 4 x + 7 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{7}{4}

5 w^{2} - 11 w = 12

6 x^{2} - 0.2 x - 0.48 = 0

x, x^{2} + y^{2} + z^{2} = 5

6 x^{2} - 121 = 0

3 x^{2} + 2 x - 8 = 0

What are the solutions to the equation factor 8x^2+10x-7=0 ?
The solutions to the equation factor 8x^2+10x-7=0 are x= 1/2 ,x=-7/4
Find the zeros of factor 8x^2+10x-7=0
The zeros of factor 8x^2+10x-7=0 are x= 1/2 ,x=-7/4