What are the solutions to the equation 4x^2+7x-20=0 ?

The solutions to the equation 4x^2+7x-20=0 are x=(-7+3sqrt(41))/8 ,x=(-7-3sqrt(41))/8

Find the zeros of 4x^2+7x-20=0

The zeros of 4x^2+7x-20=0 are x=(-7+3sqrt(41))/8 ,x=(-7-3sqrt(41))/8

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4 x^{2} + 7 x - 20 = 0

x = \frac{- 7 + 3 41}{8}, x = \frac{- 7 - 3 41}{8}

Decimal Notation

x = 1.52617 \dots, x = - 3.27617 \dots

Solution steps

4 x^{2} + 7 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 20) = 341

x_{1, 2} = \frac{- 7 \pm 3 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 3 41}{2 \cdot 4}, x_{2} = \frac{- 7 - 3 41}{2 \cdot 4}

x = \frac{- 7 + 3 41}{2 \cdot 4} : \frac{- 7 + 3 41}{8}

x = \frac{- 7 - 3 41}{2 \cdot 4} : \frac{- 7 - 3 41}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 3 41}{8}, x = \frac{- 7 - 3 41}{8}

x, x^{2} y^{2} + 2 x^{2} - 4 = 0

x, 36 x^{2} + 100 y^{2} + 225 z^{2} = 12600

n^{2} - 2 n - 48 = 0

12 m^{2} + 6 m = 0

x, 3 x^{2} + 2 x y^{3} = 0

What are the solutions to the equation 4x^2+7x-20=0 ?
The solutions to the equation 4x^2+7x-20=0 are x=(-7+3sqrt(41))/8 ,x=(-7-3sqrt(41))/8
Find the zeros of 4x^2+7x-20=0
The zeros of 4x^2+7x-20=0 are x=(-7+3sqrt(41))/8 ,x=(-7-3sqrt(41))/8