What are the solutions to the equation x^2-10x-19=0 ?

The solutions to the equation x^2-10x-19=0 are x=5+2sqrt(11),x=5-2sqrt(11)

Find the zeros of x^2-10x-19=0

The zeros of x^2-10x-19=0 are x=5+2sqrt(11),x=5-2sqrt(11)

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x^{2} - 10 x - 19 = 0

x = 5 + 211, x = 5 - 211

Decimal Notation

x = 11.63324 \dots, x = - 1.63324 \dots

Solution steps

x^{2} - 10 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 19) = 411

x_{1, 2} = \frac{- ( - 10 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 11}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 11}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 11}{2 \cdot 1} : 5 + 211

x = \frac{- ( - 10 ) - 4 11}{2 \cdot 1} : 5 - 211

The solutions to the quadratic equation are:

x = 5 + 211, x = 5 - 211

(3 x - 5) (7 - 5 x) + (5 x + 2) (2 x - 2) - 2 = 0

y, 2 x = y^{2}

y^{2} - 14 y + 24 = 0

x^{2} + 20 x + 2600 = 0

9 - 8 x - x^{2}

What are the solutions to the equation x^2-10x-19=0 ?
The solutions to the equation x^2-10x-19=0 are x=5+2sqrt(11),x=5-2sqrt(11)
Find the zeros of x^2-10x-19=0
The zeros of x^2-10x-19=0 are x=5+2sqrt(11),x=5-2sqrt(11)