What is the answer to 6(4x-3)+7(x+1)=9 ?

The answer to 6(4x-3)+7(x+1)=9 is x= 20/31

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6(4x-3)+7(x+1)=9

6 (4 x - 3) + 7 (x + 1) = 9

x = \frac{20}{31}

Decimal Notation

x = 0.64516 \dots

Solution steps

6 (4 x - 3) + 7 (x + 1) = 9

Expand

6 (4 x - 3) + 7 (x + 1) : 31 x - 11

31 x - 11 = 9

Move

11

to the right side

31 x = 20

Divide both sides by

31

x = \frac{20}{31}

\frac{7 !}{( 7 - 4 ) ! 4 !}

31 = m^{2}

2.4 = 4 t^{2}

(x + h - x) (x + h + x)

42 - 6 u^{3} - 7 v^{2} + u^{3} v^{2}

What is the answer to 6(4x-3)+7(x+1)=9 ?
The answer to 6(4x-3)+7(x+1)=9 is x= 20/31
Solve for x: 6(4x-3)+7(x+1)=9
The solution is x= 20/31