What are the solutions to the equation x^2+6x+11=3 ?

The solutions to the equation x^2+6x+11=3 are x=-2,x=-4

Find the zeros of x^2+6x+11=3

The zeros of x^2+6x+11=3 are x=-2,x=-4

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x^{2} + 6 x + 11 = 3

x = - 2, x = - 4

Solution steps

x^{2} + 6 x + 11 = 3

Move

3

to the left side

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

y^{2} - 3 y + 10 = 0

2 x^{2} + 9 x + 3 = 8

(y - 2)^{2} = - y^{2} + 10

r^{2} + 5 r - 3 = 0

6 x^{2} = 384

What are the solutions to the equation x^2+6x+11=3 ?
The solutions to the equation x^2+6x+11=3 are x=-2,x=-4
Find the zeros of x^2+6x+11=3
The zeros of x^2+6x+11=3 are x=-2,x=-4