What are the solutions to the equation w^2-47w=0 ?

The solutions to the equation w^2-47w=0 are w=47,w=0

Find the zeros of w^2-47w=0

The zeros of w^2-47w=0 are w=47,w=0

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w^{2} - 47 w = 0

w = 47, w = 0

Solution steps

w^{2} - 47 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 47 ) \pm ( - 47 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 47)^{2} - 4 \cdot 1 \cdot 0 = 47

w_{1, 2} = \frac{- ( - 47 ) \pm 47}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 47 ) + 47}{2 \cdot 1}, w_{2} = \frac{- ( - 47 ) - 47}{2 \cdot 1}

w = \frac{- ( - 47 ) + 47}{2 \cdot 1} : 47

w = \frac{- ( - 47 ) - 47}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

w = 47, w = 0

(3 p + 2)^{2} = 12

r^{2} + 4 r + \frac{76}{3} = 0

\frac{1}{4} y^{2} - \frac{3}{5} y - \frac{1}{4} = 0

x (x + 3) = 8 x - 2

0 = 16 - x^{2}

What are the solutions to the equation w^2-47w=0 ?
The solutions to the equation w^2-47w=0 are w=47,w=0
Find the zeros of w^2-47w=0
The zeros of w^2-47w=0 are w=47,w=0