What are the solutions to the equation x^2+3x-35=3x+13x+1 ?

The solutions to the equation x^2+3x-35=3x+13x+1 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2

Find the zeros of x^2+3x-35=3x+13x+1

The zeros of x^2+3x-35=3x+13x+1 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2

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x^{2} + 3 x - 35 = 3 x + 13 x + 1

x = \frac{13 + 313}{2}, x = \frac{13 - 313}{2}

Decimal Notation

x = 15.34590 \dots, x = - 2.34590 \dots

Solution steps

x^{2} + 3 x - 35 = 3 x + 13 x + 1

Refine

x^{2} + 3 x - 35 = 16 x + 1

Move

1

to the left side

x^{2} + 3 x - 36 = 16 x

Move

16 x

to the left side

x^{2} - 13 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 36) = 313

x_{1, 2} = \frac{- ( - 13 ) \pm 313}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 313}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 313}{2 \cdot 1}

x = \frac{- ( - 13 ) + 313}{2 \cdot 1} : \frac{13 + 313}{2}

x = \frac{- ( - 13 ) - 313}{2 \cdot 1} : \frac{13 - 313}{2}

The solutions to the quadratic equation are:

x = \frac{13 + 313}{2}, x = \frac{13 - 313}{2}

15 + 0.005 V^{1} = 10 + 0.02 V^{2}

(x^{2} + 4 x + 13) = 0

x, x^{2} - y^{2} - z^{2} + 4 x - 6 y + 2 z - 16 = 0

1 x^{2} + 3 x + 4 = 0

2 x^{2} - 1 = 49

What are the solutions to the equation x^2+3x-35=3x+13x+1 ?
The solutions to the equation x^2+3x-35=3x+13x+1 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2
Find the zeros of x^2+3x-35=3x+13x+1
The zeros of x^2+3x-35=3x+13x+1 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2