What are the solutions to the equation 8x^2-7x=-1 ?

The solutions to the equation 8x^2-7x=-1 are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)

Find the zeros of 8x^2-7x=-1

The zeros of 8x^2-7x=-1 are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)

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8 x^{2} - 7 x = - 1

x = \frac{7 + 17}{16}, x = \frac{7 - 17}{16}

Decimal Notation

x = 0.69519 \dots, x = 0.17980 \dots

Solution steps

8 x^{2} - 7 x = - 1

Move

1

to the left side

8 x^{2} - 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 \cdot 1 = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 8}

x = \frac{- ( - 7 ) + 17}{2 \cdot 8} : \frac{7 + 17}{16}

x = \frac{- ( - 7 ) - 17}{2 \cdot 8} : \frac{7 - 17}{16}

The solutions to the quadratic equation are:

x = \frac{7 + 17}{16}, x = \frac{7 - 17}{16}

\frac{1}{2} x^{2} + x - 1 = 0

- x^{2} - 1 - 2 x^{2} = 0

x, m x^{2} + 2 m x = 3 x^{2} + m + 1

(3 x - 4)^{2} + (2 x - 3) (x + 5) = - (x^{2} + x + 3)

(3 - x) (- 3 - x) + 10 = 0

What are the solutions to the equation 8x^2-7x=-1 ?
The solutions to the equation 8x^2-7x=-1 are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)
Find the zeros of 8x^2-7x=-1
The zeros of 8x^2-7x=-1 are x=(7+sqrt(17))/(16),x=(7-sqrt(17))/(16)