What are the solutions to the equation 12x^2+48x+45=0 ?

The solutions to the equation 12x^2+48x+45=0 are x=-3/2 ,x=-5/2

Find the zeros of 12x^2+48x+45=0

The zeros of 12x^2+48x+45=0 are x=-3/2 ,x=-5/2

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12 x^{2} + 48 x + 45 = 0

x = - \frac{3}{2}, x = - \frac{5}{2}

Decimal Notation

x = - 1.5, x = - 2.5

Solution steps

12 x^{2} + 48 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 12 \cdot 45}{2 \cdot 12}

4 8^{2} - 4 \cdot 12 \cdot 45 = 12

x_{1, 2} = \frac{- 48 \pm 12}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 48 + 12}{2 \cdot 12}, x_{2} = \frac{- 48 - 12}{2 \cdot 12}

x = \frac{- 48 + 12}{2 \cdot 12} : - \frac{3}{2}

x = \frac{- 48 - 12}{2 \cdot 12} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{5}{2}

4 x^{2} - 6 x - 8 = - 2 x - 5

4 x^{2} - 11 x - 45 = 0

15495.87 x^{2} + 231829.74 x - 19620 = 0

x, x^{2} + y^{2} + a x + b y + c = 0

54 - 3 x^{2} = 0

What are the solutions to the equation 12x^2+48x+45=0 ?
The solutions to the equation 12x^2+48x+45=0 are x=-3/2 ,x=-5/2
Find the zeros of 12x^2+48x+45=0
The zeros of 12x^2+48x+45=0 are x=-3/2 ,x=-5/2