What are the solutions to the equation -3x^2-2x=-3 ?

The solutions to the equation -3x^2-2x=-3 are x=-(1+sqrt(10))/3 ,x=(sqrt(10)-1)/3

Find the zeros of -3x^2-2x=-3

The zeros of -3x^2-2x=-3 are x=-(1+sqrt(10))/3 ,x=(sqrt(10)-1)/3

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- 3 x^{2} - 2 x = - 3

x = - \frac{1 + 10}{3}, x = \frac{10 - 1}{3}

Decimal Notation

x = - 1.38742 \dots, x = 0.72075 \dots

Solution steps

- 3 x^{2} - 2 x = - 3

Move

3

to the left side

- 3 x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 3}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 3 = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 2 10}{2 ( - 3 )} : - \frac{1 + 10}{3}

x = \frac{- ( - 2 ) - 2 10}{2 ( - 3 )} : \frac{10 - 1}{3}

The solutions to the quadratic equation are:

x = - \frac{1 + 10}{3}, x = \frac{10 - 1}{3}

L (2000) = 2 v^{2} + 50 v + 10

x [x + 8 (x - 6)] = 7 - [5 - (2 x + 5)]

4 x^{2} = 24 x - 8 x^{2}

y, 3 = e^{- 2 x} (2 y^{2} + 2 x^{2} + 2 x + 1)

\frac{25}{3} x^{2} - 3 = 0

What are the solutions to the equation -3x^2-2x=-3 ?
The solutions to the equation -3x^2-2x=-3 are x=-(1+sqrt(10))/3 ,x=(sqrt(10)-1)/3
Find the zeros of -3x^2-2x=-3
The zeros of -3x^2-2x=-3 are x=-(1+sqrt(10))/3 ,x=(sqrt(10)-1)/3