What are the solutions to the equation quadraticformula 2x^2-14x+10=26 ?

The solutions to the equation quadraticformula 2x^2-14x+10=26 are x=8,x=-1

Find the zeros of quadraticformula 2x^2-14x+10=26

The zeros of quadraticformula 2x^2-14x+10=26 are x=8,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 14 x + 10 = 26

x = 8, x = - 1

Solution steps

2 x^{2} - 14 x + 10 = 26

Move

26

to the left side

2 x^{2} - 14 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 ( - 16 )}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 (- 16) = 18

x_{1, 2} = \frac{- ( - 14 ) \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 18}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 18}{2 \cdot 2}

x = \frac{- ( - 14 ) + 18}{2 \cdot 2} : 8

x = \frac{- ( - 14 ) - 18}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

5 r^{2} + 215 r + 3 = 0

x^{2} + 4 x = 252

2 x^{2} - 22 x - 24 = 0

x^{2} - 5 x - 25 = 4

4 x + 12 = x^{2}

What are the solutions to the equation quadraticformula 2x^2-14x+10=26 ?
The solutions to the equation quadraticformula 2x^2-14x+10=26 are x=8,x=-1
Find the zeros of quadraticformula 2x^2-14x+10=26
The zeros of quadraticformula 2x^2-14x+10=26 are x=8,x=-1