What are the solutions to the equation v^2=11v ?

The solutions to the equation v^2=11v are v=11,v=0

Find the zeros of v^2=11v

The zeros of v^2=11v are v=11,v=0

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v^{2} = 11 v

v = 11, v = 0

Solution steps

v^{2} = 11 v

Move

11 v

to the left side

v^{2} - 11 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 0 = 11

v_{1, 2} = \frac{- ( - 11 ) \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 11 ) + 11}{2 \cdot 1}, v_{2} = \frac{- ( - 11 ) - 11}{2 \cdot 1}

v = \frac{- ( - 11 ) + 11}{2 \cdot 1} : 11

v = \frac{- ( - 11 ) - 11}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

v = 11, v = 0

20 x^{2} + 49 x + 30 = 0

4 b^{2} - 5 b - 3 = 2 b

2 x^{2} + 9 x = 8

\frac{7}{4} x^{2} - 2 = - 0.5 x + 4

b, a^{2} = b^{2} + 9.2

What are the solutions to the equation v^2=11v ?
The solutions to the equation v^2=11v are v=11,v=0
Find the zeros of v^2=11v
The zeros of v^2=11v are v=11,v=0