What are the solutions to the equation x^2+6x+3=19 ?

The solutions to the equation x^2+6x+3=19 are x=2,x=-8

Find the zeros of x^2+6x+3=19

The zeros of x^2+6x+3=19 are x=2,x=-8

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x^{2} + 6 x + 3 = 19

x = 2, x = - 8

Solution steps

x^{2} + 6 x + 3 = 19

Move

19

to the left side

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

x^{2} - 13 x - 318.75 = 0

3 k^{2} - 58 k + 240 = 0

x, \frac{( z - 4 ) ^{2}}{4} - \frac{y ^{2}}{3} - 3 x^{2} = 1

3 ab x^{2} - 5 a^{2} b x - 2 a b^{2} x = 4 ab x (x - b) - a^{2} b (x - b)

x^{2} - 3 x - 18

What are the solutions to the equation x^2+6x+3=19 ?
The solutions to the equation x^2+6x+3=19 are x=2,x=-8
Find the zeros of x^2+6x+3=19
The zeros of x^2+6x+3=19 are x=2,x=-8