What are the solutions to the equation 25x^2-49=0 ?

The solutions to the equation 25x^2-49=0 are x= 7/5 ,x=-7/5

Find the zeros of 25x^2-49=0

The zeros of 25x^2-49=0 are x= 7/5 ,x=-7/5

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25 x^{2} - 49 = 0

x = \frac{7}{5}, x = - \frac{7}{5}

Decimal Notation

x = 1.4, x = - 1.4

Solution steps

25 x^{2} - 49 = 0

Move

49

to the right side

25 x^{2} = 49

Divide both sides by

25

x^{2} = \frac{49}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{25}, x = - \frac{49}{25}

\frac{49}{25} = \frac{7}{5}

- \frac{49}{25} = - \frac{7}{5}

x = \frac{7}{5}, x = - \frac{7}{5}

∣ 2 x + 1 ∣ \leq 1

r^{2} - 10 r + 29 = 0

\frac{- 3}{2} + 1

(x + 3)^{2} - 6 = 19

What are the solutions to the equation 25x^2-49=0 ?
The solutions to the equation 25x^2-49=0 are x= 7/5 ,x=-7/5
Find the zeros of 25x^2-49=0
The zeros of 25x^2-49=0 are x= 7/5 ,x=-7/5