What are the solutions to the equation r^2+5r-72=0 ?

The solutions to the equation r^2+5r-72=0 are r=(-5+sqrt(313))/2 ,r=(-5-sqrt(313))/2

Find the zeros of r^2+5r-72=0

The zeros of r^2+5r-72=0 are r=(-5+sqrt(313))/2 ,r=(-5-sqrt(313))/2

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r^{2} + 5 r - 72 = 0

r = \frac{- 5 + 313}{2}, r = \frac{- 5 - 313}{2}

Decimal Notation

r = 6.34590 \dots, r = - 11.34590 \dots

Solution steps

r^{2} + 5 r - 72 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 72) = 313

r_{1, 2} = \frac{- 5 \pm 313}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 5 + 313}{2 \cdot 1}, r_{2} = \frac{- 5 - 313}{2 \cdot 1}

r = \frac{- 5 + 313}{2 \cdot 1} : \frac{- 5 + 313}{2}

r = \frac{- 5 - 313}{2 \cdot 1} : \frac{- 5 - 313}{2}

The solutions to the quadratic equation are:

r = \frac{- 5 + 313}{2}, r = \frac{- 5 - 313}{2}

2 x^{2} - x = 14

(3 x)^{2} = (x + 4)^{2} + (2 x - 3)^{2}

y, x^{2} + y^{2} = 2 x

x, x^{2} + 8 x + y^{2} + 6 y + 26 = 0

- x^{2} - 9 x + 11 = x

What are the solutions to the equation r^2+5r-72=0 ?
The solutions to the equation r^2+5r-72=0 are r=(-5+sqrt(313))/2 ,r=(-5-sqrt(313))/2
Find the zeros of r^2+5r-72=0
The zeros of r^2+5r-72=0 are r=(-5+sqrt(313))/2 ,r=(-5-sqrt(313))/2