What are the solutions to the equation k^2+10k-3=0 ?

The solutions to the equation k^2+10k-3=0 are k=-5+2sqrt(7),k=-5-2sqrt(7)

Find the zeros of k^2+10k-3=0

The zeros of k^2+10k-3=0 are k=-5+2sqrt(7),k=-5-2sqrt(7)

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k^{2} + 10 k - 3 = 0

k = - 5 + 27, k = - 5 - 27

Decimal Notation

k = 0.29150 \dots, k = - 10.29150 \dots

Solution steps

k^{2} + 10 k - 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 3) = 47

k_{1, 2} = \frac{- 10 \pm 4 7}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 10 + 4 7}{2 \cdot 1}, k_{2} = \frac{- 10 - 4 7}{2 \cdot 1}

k = \frac{- 10 + 4 7}{2 \cdot 1} : - 5 + 27

k = \frac{- 10 - 4 7}{2 \cdot 1} : - 5 - 27

The solutions to the quadratic equation are:

k = - 5 + 27, k = - 5 - 27

x, 2 x^{2} - 5 x + 3 = 0

x^{2} - 8 = 12

4 - 2 x + x^{2} = 0

2 a^{2} - 3 a + \frac{1}{4} = 0

45 - 19 x + 2 x^{2} = 0

What are the solutions to the equation k^2+10k-3=0 ?
The solutions to the equation k^2+10k-3=0 are k=-5+2sqrt(7),k=-5-2sqrt(7)
Find the zeros of k^2+10k-3=0
The zeros of k^2+10k-3=0 are k=-5+2sqrt(7),k=-5-2sqrt(7)