What are the solutions to the equation x^2+a^2-2x-6a=6x-2a ?

The solutions to the equation x^2+a^2-2x-6a=6x-2a are x=4+sqrt(-a(a-4)+16),x=4-sqrt(-a(a-4)+16)

Find the zeros of x^2+a^2-2x-6a=6x-2a

The zeros of x^2+a^2-2x-6a=6x-2a are x=4+sqrt(-a(a-4)+16),x=4-sqrt(-a(a-4)+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + a^{2} - 2 x - 6 a = 6 x - 2 a

x = 4 + - a (a - 4) + 16, x = 4 - - a (a - 4) + 16

Solution steps

x^{2} + a^{2} - 2 x - 6 a = 6 x - 2 a

Move

2 a

to the left side

x^{2} + a^{2} - 2 x - 4 a = 6 x

Move

6 x

to the left side

x^{2} - 8 x + a^{2} - 4 a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( a ^{2} - 4 a )}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot (a^{2} - 4 a) : 2 16 - a (a - 4)

x_{1, 2} = \frac{- ( - 8 ) \pm 2 16 - a ( a - 4 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 16 - a ( a - 4 )}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 16 - a ( a - 4 )}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 16 - a ( a - 4 )}{2 \cdot 1} : 4 + - a (a - 4) + 16

x = \frac{- ( - 8 ) - 2 16 - a ( a - 4 )}{2 \cdot 1} : 4 - - a (a - 4) + 16

The solutions to the quadratic equation are:

x = 4 + - a (a - 4) + 16, x = 4 - - a (a - 4) + 16

2 x^{2} + 4 x = - 3 x^{2} + x - 5

m^{2} = 4 m

- 3 x^{2} - 1200 x + 12488 = 0

x, (x - xv)^{2} = 2 p (yy v)

y (y + 4) = 0

What are the solutions to the equation x^2+a^2-2x-6a=6x-2a ?
The solutions to the equation x^2+a^2-2x-6a=6x-2a are x=4+sqrt(-a(a-4)+16),x=4-sqrt(-a(a-4)+16)
Find the zeros of x^2+a^2-2x-6a=6x-2a
The zeros of x^2+a^2-2x-6a=6x-2a are x=4+sqrt(-a(a-4)+16),x=4-sqrt(-a(a-4)+16)