What are the solutions to the equation 196x^2+25=0 ?

The solutions to the equation 196x^2+25=0 are x= 5/14 i,x=-5/14 i

Find the zeros of 196x^2+25=0

The zeros of 196x^2+25=0 are x= 5/14 i,x=-5/14 i

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196 x^{2} + 25 = 0

x = \frac{5}{14} i, x = - \frac{5}{14} i

Solution steps

196 x^{2} + 25 = 0

Move

25

to the right side

196 x^{2} = - 25

Divide both sides by

196

x^{2} = - \frac{25}{196}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{25}{196}, x = - - \frac{25}{196}

- \frac{25}{196} = \frac{5}{14} i

- - \frac{25}{196} = - \frac{5}{14} i

x = \frac{5}{14} i, x = - \frac{5}{14} i

4 v^{2} = 2 - 2 v

4.9 x^{2} - 39.2 x + 58.8 = 0

5 x^{2} + 12 x = 0

2 x^{2} + x^{2} = 100

x^{2} + 14 x + 43 = 0

What are the solutions to the equation 196x^2+25=0 ?
The solutions to the equation 196x^2+25=0 are x= 5/14 i,x=-5/14 i
Find the zeros of 196x^2+25=0
The zeros of 196x^2+25=0 are x= 5/14 i,x=-5/14 i