What are the solutions to the equation 3x^2+6x+8+7x^2-3x=9 ?

The solutions to the equation 3x^2+6x+8+7x^2-3x=9 are x= 1/5 ,x=-1/2

Find the zeros of 3x^2+6x+8+7x^2-3x=9

The zeros of 3x^2+6x+8+7x^2-3x=9 are x= 1/5 ,x=-1/2

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3 x^{2} + 6 x + 8 + 7 x^{2} - 3 x = 9

x = \frac{1}{5}, x = - \frac{1}{2}

Decimal Notation

x = 0.2, x = - 0.5

Solution steps

3 x^{2} + 6 x + 8 + 7 x^{2} - 3 x = 9

Refine

10 x^{2} + 3 x + 8 = 9

Move

9

to the left side

10 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

3^{2} - 4 \cdot 10 (- 1) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 10}, x_{2} = \frac{- 3 - 7}{2 \cdot 10}

x = \frac{- 3 + 7}{2 \cdot 10} : \frac{1}{5}

x = \frac{- 3 - 7}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{1}{2}

5 x^{2} + 70000 x - 6000 = 6000

x^{2} - 2 x = 15

30 x^{2} + 2 x - 4 = 0

16 t^{2} - 8 t + 1 = 0

2 x^{2} - 3 x + 1 = 15

What are the solutions to the equation 3x^2+6x+8+7x^2-3x=9 ?
The solutions to the equation 3x^2+6x+8+7x^2-3x=9 are x= 1/5 ,x=-1/2
Find the zeros of 3x^2+6x+8+7x^2-3x=9
The zeros of 3x^2+6x+8+7x^2-3x=9 are x= 1/5 ,x=-1/2