What are the solutions to the equation 775=-q^2+1000 ?

The solutions to the equation 775=-q^2+1000 are q=15,q=-15

Find the zeros of 775=-q^2+1000

The zeros of 775=-q^2+1000 are q=15,q=-15

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775 = - q^{2} + 1000

q = 15, q = - 15

Solution steps

775 = - q^{2} + 1000

Switch sides

- q^{2} + 1000 = 775

Move

1000

to the right side

- q^{2} = - 225

Divide both sides by

- 1

q^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 225, q = - 225

225 = 15

- 225 = - 15

q = 15, q = - 15

(2 x + 3) (5 x - 8) = 0

x^{2} - x - 14 = 6

- \frac{1}{2} x^{2} = - 36

m^{2} + 6 = 0

2 x^{2} + 3 x - 5 = 0

What are the solutions to the equation 775=-q^2+1000 ?
The solutions to the equation 775=-q^2+1000 are q=15,q=-15
Find the zeros of 775=-q^2+1000
The zeros of 775=-q^2+1000 are q=15,q=-15