What are the solutions to the equation 11x^2+28x+10=0 ?

The solutions to the equation 11x^2+28x+10=0 are x=(-14+sqrt(86))/(11),x=-(14+sqrt(86))/(11)

Find the zeros of 11x^2+28x+10=0

The zeros of 11x^2+28x+10=0 are x=(-14+sqrt(86))/(11),x=-(14+sqrt(86))/(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

11 x^{2} + 28 x + 10 = 0

x = \frac{- 14 + 86}{11}, x = - \frac{14 + 86}{11}

Decimal Notation

x = - 0.42967 \dots, x = - 2.11578 \dots

Solution steps

11 x^{2} + 28 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 11 \cdot 10}{2 \cdot 11}

2 8^{2} - 4 \cdot 11 \cdot 10 = 286

x_{1, 2} = \frac{- 28 \pm 2 86}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 28 + 2 86}{2 \cdot 11}, x_{2} = \frac{- 28 - 2 86}{2 \cdot 11}

x = \frac{- 28 + 2 86}{2 \cdot 11} : \frac{- 14 + 86}{11}

x = \frac{- 28 - 2 86}{2 \cdot 11} : - \frac{14 + 86}{11}

The solutions to the quadratic equation are:

x = \frac{- 14 + 86}{11}, x = - \frac{14 + 86}{11}

- 2 a^{2} + 2 a + 3 = 0

x^{2} + 6 x + 252 = 0

2 x^{2} + 16 x + 14 = 0

4 t^{2} - 5 t + 1 = 0

0 = x^{2} + 4 x - 9

What are the solutions to the equation 11x^2+28x+10=0 ?
The solutions to the equation 11x^2+28x+10=0 are x=(-14+sqrt(86))/(11),x=-(14+sqrt(86))/(11)
Find the zeros of 11x^2+28x+10=0
The zeros of 11x^2+28x+10=0 are x=(-14+sqrt(86))/(11),x=-(14+sqrt(86))/(11)