What are the solutions to the equation (3x-4)^2=5x-6 ?

The solutions to the equation (3x-4)^2=5x-6 are x=2,x= 11/9

Find the zeros of (3x-4)^2=5x-6

The zeros of (3x-4)^2=5x-6 are x=2,x= 11/9

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(3 x - 4)^{2} = 5 x - 6

x = 2, x = \frac{11}{9}

Decimal Notation

x = 2, x = 1.22222 \dots

Solution steps

(3 x - 4)^{2} = 5 x - 6

Expand

(3 x - 4)^{2} : 9 x^{2} - 24 x + 16

9 x^{2} - 24 x + 16 = 5 x - 6

Move

6

to the left side

9 x^{2} - 24 x + 22 = 5 x

Move

5 x

to the left side

9 x^{2} - 29 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 9 \cdot 22}{2 \cdot 9}

(- 29)^{2} - 4 \cdot 9 \cdot 22 = 7

x_{1, 2} = \frac{- ( - 29 ) \pm 7}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 7}{2 \cdot 9}, x_{2} = \frac{- ( - 29 ) - 7}{2 \cdot 9}

x = \frac{- ( - 29 ) + 7}{2 \cdot 9} : 2

x = \frac{- ( - 29 ) - 7}{2 \cdot 9} : \frac{11}{9}

The solutions to the quadratic equation are:

x = 2, x = \frac{11}{9}

m^{2} = - 9 m

(9.8) (6) = \frac{1}{2} v^{2}

30 (25 - t^{2}) = 450

9 x^{2} + 5 x + \frac{9}{4} = 0

x^{2} - 15 x + 4 = 0

What are the solutions to the equation (3x-4)^2=5x-6 ?
The solutions to the equation (3x-4)^2=5x-6 are x=2,x= 11/9
Find the zeros of (3x-4)^2=5x-6
The zeros of (3x-4)^2=5x-6 are x=2,x= 11/9