What are the solutions to the equation 9^2=7^2+b^2 ?

The solutions to the equation 9^2=7^2+b^2 are b=4sqrt(2),b=-4sqrt(2)

Find the zeros of 9^2=7^2+b^2

The zeros of 9^2=7^2+b^2 are b=4sqrt(2),b=-4sqrt(2)

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9^{2} = 7^{2} + b^{2}

b = 42, b = - 42

Decimal Notation

b = 5.65685 \dots, b = - 5.65685 \dots

Solution steps

9^{2} = 7^{2} + b^{2}

Switch sides

7^{2} + b^{2} = 9^{2}

Move

7^{2}

to the right side

b^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 32, b = - 32

32 = 42

- 32 = - 42

b = 42, b = - 42

(2 x - 3) (x + 7) = 0

- x^{2} + x + 30 = 0

100 = 500 - 4 x^{2}

1 - 6 x + 6 x^{2} = 0

16 x^{2} + 4 x - 6 = 0

What are the solutions to the equation 9^2=7^2+b^2 ?
The solutions to the equation 9^2=7^2+b^2 are b=4sqrt(2),b=-4sqrt(2)
Find the zeros of 9^2=7^2+b^2
The zeros of 9^2=7^2+b^2 are b=4sqrt(2),b=-4sqrt(2)