What are the solutions to the equation 3s^2+16s+12=0 ?

The solutions to the equation 3s^2+16s+12=0 are s=(2(sqrt(7)-4))/3 ,s=-(2(4+sqrt(7)))/3

Find the zeros of 3s^2+16s+12=0

The zeros of 3s^2+16s+12=0 are s=(2(sqrt(7)-4))/3 ,s=-(2(4+sqrt(7)))/3

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3 s^{2} + 16 s + 12 = 0

s = \frac{2 ( 7 - 4 )}{3}, s = - \frac{2 ( 4 + 7 )}{3}

Decimal Notation

s = - 0.90283 \dots, s = - 4.43050 \dots

Solution steps

3 s^{2} + 16 s + 12 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 12 = 47

s_{1, 2} = \frac{- 16 \pm 4 7}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 16 + 4 7}{2 \cdot 3}, s_{2} = \frac{- 16 - 4 7}{2 \cdot 3}

s = \frac{- 16 + 4 7}{2 \cdot 3} : \frac{2 ( 7 - 4 )}{3}

s = \frac{- 16 - 4 7}{2 \cdot 3} : - \frac{2 ( 4 + 7 )}{3}

The solutions to the quadratic equation are:

s = \frac{2 ( 7 - 4 )}{3}, s = - \frac{2 ( 4 + 7 )}{3}

5 (4 x - 3)^{2} - 4 (x - 9) (3 x + 5) = 9

x, x^{2} + y^{2} + z^{2} - 4 x + 6 y - 8 z = - 20

y^{2} - 14 y + 51 = 0

x^{2} + 6.2 \cdot 1 0^{- 10} - 4.65 \cdot 1 0_{- 10} = 0

- 3 x^{2} - x - 9 = 0

What are the solutions to the equation 3s^2+16s+12=0 ?
The solutions to the equation 3s^2+16s+12=0 are s=(2(sqrt(7)-4))/3 ,s=-(2(4+sqrt(7)))/3
Find the zeros of 3s^2+16s+12=0
The zeros of 3s^2+16s+12=0 are s=(2(sqrt(7)-4))/3 ,s=-(2(4+sqrt(7)))/3