What are the solutions to the equation factor n^2+3n-12=6 ?

The solutions to the equation factor n^2+3n-12=6 are n=3,n=-6

Find the zeros of factor n^2+3n-12=6

The zeros of factor n^2+3n-12=6 are n=3,n=-6

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n^{2} + 3 n - 12 = 6

n = 3, n = - 6

Solution steps

n^{2} + 3 n - 12 = 6

Move

6

to the left side

n^{2} + 3 n - 18 = 0

Factor

n^{2} + 3 n - 18 : (n - 3) (n + 6)

(n - 3) (n + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 3 = 0 or n + 6 = 0

Solve

n - 3 = 0 : n = 3

Solve

n + 6 = 0 : n = - 6

The solutions to the quadratic equation are:

n = 3, n = - 6

x^{2} + 2 x - 2 = 0

0 = - x^{2} - 4 x + 4

4 x^{2} + 5 x = 2 x^{2} + 3 x

\frac{2}{3} x - \frac{1}{2} x = \frac{3}{4} x^{2}

9 x^{2} + 8 x + 2 = 0

What are the solutions to the equation factor n^2+3n-12=6 ?
The solutions to the equation factor n^2+3n-12=6 are n=3,n=-6
Find the zeros of factor n^2+3n-12=6
The zeros of factor n^2+3n-12=6 are n=3,n=-6