What are the solutions to the equation factor 7x^2-21x-28=0 ?

The solutions to the equation factor 7x^2-21x-28=0 are x=-1,x=4

Find the zeros of factor 7x^2-21x-28=0

The zeros of factor 7x^2-21x-28=0 are x=-1,x=4

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7 x^{2} - 21 x - 28 = 0

x = - 1, x = 4

Solution steps

7 x^{2} - 21 x - 28 = 0

Factor

7 x^{2} - 21 x - 28 : 7 (x + 1) (x - 4)

7 (x + 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - 1, x = 4

a, f (a + h) = 3 (a + h)^{2} + 5 (a + h) - 2

(x - 6)^{2} = 2 (x + 18)

2 x^{2} + x - 2 = 0

z^{2} + 20 = 2 \cdot (z - 3)

(x - 2) (x + 1) = 3

What are the solutions to the equation factor 7x^2-21x-28=0 ?
The solutions to the equation factor 7x^2-21x-28=0 are x=-1,x=4
Find the zeros of factor 7x^2-21x-28=0
The zeros of factor 7x^2-21x-28=0 are x=-1,x=4