What are the solutions to the equation 10^2=a^2-29^2 ?

The solutions to the equation 10^2=a^2-29^2 are a=sqrt(941),a=-sqrt(941)

Find the zeros of 10^2=a^2-29^2

The zeros of 10^2=a^2-29^2 are a=sqrt(941),a=-sqrt(941)

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1 0^{2} = a^{2} - 2 9^{2}

a = 941, a = - 941

Decimal Notation

a = 30.67572 \dots, a = - 30.67572 \dots

Solution steps

1 0^{2} = a^{2} - 2 9^{2}

Switch sides

a^{2} - 2 9^{2} = 1 0^{2}

Move

2 9^{2}

to the right side

a^{2} = 941

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 941, a = - 941

20 = 6 + 31 t - 16 t^{2}

b^{2} - 7 b = 0

8 x^{2} - 9 = - 3 x

(2 y + 4)^{2} = 16

3 (x + 3)^{2} = 75

What are the solutions to the equation 10^2=a^2-29^2 ?
The solutions to the equation 10^2=a^2-29^2 are a=sqrt(941),a=-sqrt(941)
Find the zeros of 10^2=a^2-29^2
The zeros of 10^2=a^2-29^2 are a=sqrt(941),a=-sqrt(941)