What are the solutions to the equation X^2-X-20=0 ?

The solutions to the equation X^2-X-20=0 are X=5,X=-4

Find the zeros of X^2-X-20=0

The zeros of X^2-X-20=0 are X=5,X=-4

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X^{2} - X - 20 = 0

X = 5, X = - 4

Solution steps

X^{2} - X - 20 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

X_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

X = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

X = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = 5, X = - 4

x + 2 = x^{2} - 1

5 x + 3 = - 2 x^{2}

x, 2 x^{2} + 5 y^{2} = 0

16 y^{2} + 62 y - 45 = 0

y, y^{2} - t^{2} + 2 t y = C

What are the solutions to the equation X^2-X-20=0 ?
The solutions to the equation X^2-X-20=0 are X=5,X=-4
Find the zeros of X^2-X-20=0
The zeros of X^2-X-20=0 are X=5,X=-4