(1-2x)/(x+1)>= 2x-1

الحلّ

\frac{1 - 2 x}{x + 1} \geq 2 x - 1

x \leq - 2 or - 1 < x \leq \frac{1}{2}

تدوين الفاصل الزمني

(- \infty, - 2] \cup (- 1, \frac{1}{2}]

العشري

x \leq - 2 or - 1 < x \leq 0.5

خطوات الحلّ

\frac{1 - 2 x}{x + 1} \geq 2 x - 1

Rewrite in standard form

\frac{- 2 x ^{2} - 3 x + 2}{x + 1} \geq 0

\frac{- 2 x ^{2} - 3 x + 2}{x + 1}

حلل إلى عوامل:

\frac{- ( 2 x - 1 ) ( x + 2 )}{x + 1}

\frac{- ( 2 x - 1 ) ( x + 2 )}{x + 1} \geq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - ( 2 x - 1 ) ( x + 2 ) ) ( - 1 )}{x + 1} \leq 0 \cdot (- 1)

بسّط

\frac{( 2 x - 1 ) ( x + 2 )}{x + 1} \leq 0

ميّز المقاطع المختلفة

x \leq - 2 or - 1 < x \leq \frac{1}{2}

c^{4} - 1

(\frac{16}{3})^{2}

3 x^{2} - 12 x + 4 = 0

(\frac{29}{41})^{5}

\frac{3}{2 + 1}