What are the solutions to the equation 24x^2+162x-42=0 ?

The solutions to the equation 24x^2+162x-42=0 are x= 1/4 ,x=-7

Find the zeros of 24x^2+162x-42=0

The zeros of 24x^2+162x-42=0 are x= 1/4 ,x=-7

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24 x^{2} + 162 x - 42 = 0

x = \frac{1}{4}, x = - 7

Decimal Notation

x = 0.25, x = - 7

Solution steps

24 x^{2} + 162 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 162 \pm 16 2 ^{2} - 4 \cdot 24 ( - 42 )}{2 \cdot 24}

16 2^{2} - 4 \cdot 24 (- 42) = 174

x_{1, 2} = \frac{- 162 \pm 174}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 162 + 174}{2 \cdot 24}, x_{2} = \frac{- 162 - 174}{2 \cdot 24}

x = \frac{- 162 + 174}{2 \cdot 24} : \frac{1}{4}

x = \frac{- 162 - 174}{2 \cdot 24} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 7

x^{2} = 17 x - 72

(2 x + 3) (x - 1) = 42

(2 x + 1)^{2} = 4 x + 1

6 x^{2} + 17 x + 9 = 0

t^{2} - 82 t + 160 = 0

What are the solutions to the equation 24x^2+162x-42=0 ?
The solutions to the equation 24x^2+162x-42=0 are x= 1/4 ,x=-7
Find the zeros of 24x^2+162x-42=0
The zeros of 24x^2+162x-42=0 are x= 1/4 ,x=-7