What are the solutions to the equation 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) ?

The solutions to the equation 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) are x= 1/5 ,x=-1/5

Find the zeros of 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5)

The zeros of 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) are x= 1/5 ,x=-1/5

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\frac{1}{25} - x^{2} = 0, (\frac{2}{5}, - \frac{1}{5}, \frac{1}{5}, - \frac{2}{5})

x = \frac{1}{5}, x = - \frac{1}{5}

Decimal Notation

x = 0.2, x = - 0.2

Solution steps

\frac{1}{25} - x^{2} = 0, (\frac{2}{5}, - \frac{1}{5}, \frac{1}{5}, - \frac{2}{5})

Move

\frac{1}{25}

to the right side

- x^{2} = - \frac{1}{25}

Divide both sides by

- 1

x^{2} = \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{25}, x = - \frac{1}{25}

\frac{1}{25} = \frac{1}{5}

- \frac{1}{25} = - \frac{1}{5}

x = \frac{1}{5}, x = - \frac{1}{5}

- 5 x^{2} + 2 = x

4 y^{2} + 8 y + 4 = 0

x, z = - x^{2} + y^{2} + 1

3 x^{2} + 1 = 13

k^{2} - 18 k - 4 = 41

What are the solutions to the equation 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) ?
The solutions to the equation 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) are x= 1/5 ,x=-1/5
Find the zeros of 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5)
The zeros of 1/25-x^2=0,(2/5 ,-1/5 , 1/5 ,-2/5) are x= 1/5 ,x=-1/5