What are the solutions to the equation 2(x+1/2)^2-9/2 =0 ?

The solutions to the equation 2(x+1/2)^2-9/2 =0 are x=1,x=-2

Find the zeros of 2(x+1/2)^2-9/2 =0

The zeros of 2(x+1/2)^2-9/2 =0 are x=1,x=-2

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2 (x + \frac{1}{2})^{2} - \frac{9}{2} = 0

x = 1, x = - 2

Solution steps

2 (x + \frac{1}{2})^{2} - \frac{9}{2} = 0

Move

\frac{9}{2}

to the right side

2 (x + \frac{1}{2})^{2} = \frac{9}{2}

Divide both sides by

2

(x + \frac{1}{2})^{2} = \frac{9}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + \frac{1}{2} = \frac{9}{4} : x = 1

Solve

x + \frac{1}{2} = - \frac{9}{4} : x = - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

2 x^{2} + 7 x + 3 = 0

x^{2} - 2 x + 1 = - x^{2} + 3 x + 4

u, v^{2} = u^{2} - 2 a s

m, F = \frac{G mm}{r ^{2}}

r^{2} - 6 r + 3 = 0

What are the solutions to the equation 2(x+1/2)^2-9/2 =0 ?
The solutions to the equation 2(x+1/2)^2-9/2 =0 are x=1,x=-2
Find the zeros of 2(x+1/2)^2-9/2 =0
The zeros of 2(x+1/2)^2-9/2 =0 are x=1,x=-2