What are the solutions to the equation y^2=20-y ?

The solutions to the equation y^2=20-y are y=4,y=-5

Find the zeros of y^2=20-y

The zeros of y^2=20-y are y=4,y=-5

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y^{2} = 20 - y

y = 4, y = - 5

Solution steps

y^{2} = 20 - y

Move

y

to the left side

y^{2} + y = 20

Move

20

to the left side

y^{2} + y - 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

y_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 1 + 9}{2 \cdot 1}, y_{2} = \frac{- 1 - 9}{2 \cdot 1}

y = \frac{- 1 + 9}{2 \cdot 1} : 4

y = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = 4, y = - 5

x, p^{2} x^{2} - 9 x^{2} - 6 x - 1 = 0

x^{2} - 4 x + 4 = \frac{225}{9}

(2 x + 3) (5 x - 7) = 0

5 y^{2} - 16 y + 11 = 0

x, y^{3} + x y^{2} - 4 x y - 4 x^{2} = 0

What are the solutions to the equation y^2=20-y ?
The solutions to the equation y^2=20-y are y=4,y=-5
Find the zeros of y^2=20-y
The zeros of y^2=20-y are y=4,y=-5