What are the solutions to the equation (3x-2)(3x+2)=77 ?

The solutions to the equation (3x-2)(3x+2)=77 are x=3,x=-3

Find the zeros of (3x-2)(3x+2)=77

The zeros of (3x-2)(3x+2)=77 are x=3,x=-3

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(3 x - 2) (3 x + 2) = 77

x = 3, x = - 3

Solution steps

(3 x - 2) (3 x + 2) = 77

Expand

(3 x - 2) (3 x + 2) : 9 x^{2} - 4

9 x^{2} - 4 = 77

Move

77

to the left side

9 x^{2} - 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 9 ( - 81 )}{2 \cdot 9}

0^{2} - 4 \cdot 9 (- 81) = 54

x_{1, 2} = \frac{- 0 \pm 54}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 0 + 54}{2 \cdot 9}, x_{2} = \frac{- 0 - 54}{2 \cdot 9}

x = \frac{- 0 + 54}{2 \cdot 9} : 3

x = \frac{- 0 - 54}{2 \cdot 9} : - 3

The solutions to the quadratic equation are:

x = 3, x = - 3

6.53 t^{2} = 49

\frac{1}{10} x^{2} - 13 = - 3

z^{2} + 10 z + 21 = 0

4 x^{2} + 3 x + 3 = 4

5^{2} = 2. 5^{2} + x^{2}

What are the solutions to the equation (3x-2)(3x+2)=77 ?
The solutions to the equation (3x-2)(3x+2)=77 are x=3,x=-3
Find the zeros of (3x-2)(3x+2)=77
The zeros of (3x-2)(3x+2)=77 are x=3,x=-3