What are the solutions to the equation h^2=7^2+4^2 ?

The solutions to the equation h^2=7^2+4^2 are h=sqrt(65),h=-sqrt(65)

Find the zeros of h^2=7^2+4^2

The zeros of h^2=7^2+4^2 are h=sqrt(65),h=-sqrt(65)

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h^{2} = 7^{2} + 4^{2}

h = 65, h = - 65

Decimal Notation

h = 8.06225 \dots, h = - 8.06225 \dots

Solution steps

h^{2} = 7^{2} + 4^{2}

Simplify

7^{2} + 4^{2} : 65

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 65, h = - 65

4 q^{2} + 3 q = 3 q^{2} - 2 q + 14

\frac{3 x ^{2} + 8 x + 8}{24} - \frac{x ( x - 3 )}{4} = x

4 u^{2} = 8 u

1 0^{2} + x^{2} = 1 4^{2}

2 y^{2} + y - 1 = 0, 2 sin^{2} (x) + sin (x) - 1 = 0

What are the solutions to the equation h^2=7^2+4^2 ?
The solutions to the equation h^2=7^2+4^2 are h=sqrt(65),h=-sqrt(65)
Find the zeros of h^2=7^2+4^2
The zeros of h^2=7^2+4^2 are h=sqrt(65),h=-sqrt(65)