What are the solutions to the equation x^2+107x-330=0 ?

The solutions to the equation x^2+107x-330=0 are x=3,x=-110

Find the zeros of x^2+107x-330=0

The zeros of x^2+107x-330=0 are x=3,x=-110

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x^{2} + 107 x - 330 = 0

x = 3, x = - 110

Solution steps

x^{2} + 107 x - 330 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 107 \pm 10 7 ^{2} - 4 \cdot 1 \cdot ( - 330 )}{2 \cdot 1}

10 7^{2} - 4 \cdot 1 \cdot (- 330) = 113

x_{1, 2} = \frac{- 107 \pm 113}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 107 + 113}{2 \cdot 1}, x_{2} = \frac{- 107 - 113}{2 \cdot 1}

x = \frac{- 107 + 113}{2 \cdot 1} : 3

x = \frac{- 107 - 113}{2 \cdot 1} : - 110

The solutions to the quadratic equation are:

x = 3, x = - 110

4 z (z - 3) = 0

4 a^{2} - 4 a + 1 = 0

- (\frac{x - 1.82}{500}) = 0.015 (1 - \frac{x}{- 8})^{2}

x^{2} - 3 x + 30 = 0

x, C y^{2} + 4 y = 2 x^{2}

What are the solutions to the equation x^2+107x-330=0 ?
The solutions to the equation x^2+107x-330=0 are x=3,x=-110
Find the zeros of x^2+107x-330=0
The zeros of x^2+107x-330=0 are x=3,x=-110