What are the solutions to the equation 3x^2-24x-36=0 ?

The solutions to the equation 3x^2-24x-36=0 are x=2(2+sqrt(7)),x=2(2-sqrt(7))

Find the zeros of 3x^2-24x-36=0

The zeros of 3x^2-24x-36=0 are x=2(2+sqrt(7)),x=2(2-sqrt(7))

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3 x^{2} - 24 x - 36 = 0

x = 2 (2 + 7), x = 2 (2 - 7)

Decimal Notation

x = 9.29150 \dots, x = - 1.29150 \dots

Solution steps

3 x^{2} - 24 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 (- 36) = 127

x_{1, 2} = \frac{- ( - 24 ) \pm 12 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 7}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 12 7}{2 \cdot 3}

x = \frac{- ( - 24 ) + 12 7}{2 \cdot 3} : 2 (2 + 7)

x = \frac{- ( - 24 ) - 12 7}{2 \cdot 3} : 2 (2 - 7)

The solutions to the quadratic equation are:

x = 2 (2 + 7), x = 2 (2 - 7)

- 3 y^{2} + 120 y - 900 = 0

2 x^{2} - 8 x - 2 = 3

2 x^{2} - 5 x + 2

- 5 x^{2} + 3 x + 2 = 0

s^{2} + 3 s + 80 = 0

What are the solutions to the equation 3x^2-24x-36=0 ?
The solutions to the equation 3x^2-24x-36=0 are x=2(2+sqrt(7)),x=2(2-sqrt(7))
Find the zeros of 3x^2-24x-36=0
The zeros of 3x^2-24x-36=0 are x=2(2+sqrt(7)),x=2(2-sqrt(7))