What are the solutions to the equation b^2=5 ?

The solutions to the equation b^2=5 are b=sqrt(5),b=-sqrt(5)

Find the zeros of b^2=5

The zeros of b^2=5 are b=sqrt(5),b=-sqrt(5)

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b^{2} = 5

b = 5, b = - 5

Decimal Notation

b = 2.23606 \dots, b = - 2.23606 \dots

Solution steps

b^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 5, b = - 5

(x + 2)^{2} - 3 (x + 2) - 4 = 0

18 x^{2} + 24 = 0

1250000 + 60000 x - 6000 x^{2} = 0

x^{2} - 40 x + 240 = 0

x^{2} - 4 x + 3 = 2 x^{2} + 2 x + 3

What are the solutions to the equation b^2=5 ?
The solutions to the equation b^2=5 are b=sqrt(5),b=-sqrt(5)
Find the zeros of b^2=5
The zeros of b^2=5 are b=sqrt(5),b=-sqrt(5)