What are the solutions to the equation 2(x^2+1)=5x ?

The solutions to the equation 2(x^2+1)=5x are x=2,x= 1/2

Find the zeros of 2(x^2+1)=5x

The zeros of 2(x^2+1)=5x are x=2,x= 1/2

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2 (x^{2} + 1) = 5 x

x = 2, x = \frac{1}{2}

Decimal Notation

x = 2, x = 0.5

Solution steps

2 (x^{2} + 1) = 5 x

Expand

2 (x^{2} + 1) : 2 x^{2} + 2

2 x^{2} + 2 = 5 x

Move

5 x

to the left side

2 x^{2} + 2 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

x = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{2}

4 x^{2} - 2 x - 4 = 0

x, f = s g n (x^{2} - x - 6)

21 x^{2} + 28 x + 8 = 0

x, y x^{2} - 4 y - x^{2} = 0

x + x^{2} - 25 = + 15 x + 47

What are the solutions to the equation 2(x^2+1)=5x ?
The solutions to the equation 2(x^2+1)=5x are x=2,x= 1/2
Find the zeros of 2(x^2+1)=5x
The zeros of 2(x^2+1)=5x are x=2,x= 1/2