What are the solutions to the equation -5t^2+14t+3=0 ?

The solutions to the equation -5t^2+14t+3=0 are t=-1/5 ,t=3

Find the zeros of -5t^2+14t+3=0

The zeros of -5t^2+14t+3=0 are t=-1/5 ,t=3

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- 5 t^{2} + 14 t + 3 = 0

t = - \frac{1}{5}, t = 3

Decimal Notation

t = - 0.2, t = 3

Solution steps

- 5 t^{2} + 14 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

1 4^{2} - 4 (- 5) \cdot 3 = 16

t_{1, 2} = \frac{- 14 \pm 16}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 14 + 16}{2 ( - 5 )}, t_{2} = \frac{- 14 - 16}{2 ( - 5 )}

t = \frac{- 14 + 16}{2 ( - 5 )} : - \frac{1}{5}

t = \frac{- 14 - 16}{2 ( - 5 )} : 3

The solutions to the quadratic equation are:

t = - \frac{1}{5}, t = 3

4 x^{2} - 11 x + 3 = 0

9 x^{2} + 12 x + 6 = 0

2 x^{2} + 5 x + 3 = 0

x, 9 x^{2} - 12 x y + 4 y^{2} + 38 x - 60 y + 121 = 0

- 6 x^{2} + 24 x + 30 = 0

What are the solutions to the equation -5t^2+14t+3=0 ?
The solutions to the equation -5t^2+14t+3=0 are t=-1/5 ,t=3
Find the zeros of -5t^2+14t+3=0
The zeros of -5t^2+14t+3=0 are t=-1/5 ,t=3