What are the solutions to the equation solvefor x,9x^2y-4xy^2=0 ?

The solutions to the equation solvefor x,9x^2y-4xy^2=0 are x=(4y)/9 ,x=0;\quad y\ne 0

Find the zeros of solvefor x,9x^2y-4xy^2=0

The zeros of solvefor x,9x^2y-4xy^2=0 are x=(4y)/9 ,x=0;\quad y\ne 0

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solve for

x, 9 x^{2} y - 4 x y^{2} = 0

x = \frac{4 y}{9}, x = 0; y \neq = 0

Solution steps

9 x^{2} y - 4 x y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

9 y x^{2} - 4 y^{2} x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 y ^{2} ) \pm ( - 4 y ^{2} ) ^{2} - 4 \cdot 9 y \cdot 0}{2 \cdot 9 y}

Simplify

(- 4 y^{2})^{2} - 4 \cdot 9 y \cdot 0 : 4 y^{2}

x_{1, 2} = \frac{- ( - 4 y ^{2} ) \pm 4 y ^{2}}{2 \cdot 9 y}; y \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 4 y ^{2} ) + 4 y ^{2}}{2 \cdot 9 y}, x_{2} = \frac{- ( - 4 y ^{2} ) - 4 y ^{2}}{2 \cdot 9 y}

x = \frac{- ( - 4 y ^{2} ) + 4 y ^{2}}{2 \cdot 9 y} : \frac{4 y}{9}

x = \frac{- ( - 4 y ^{2} ) - 4 y ^{2}}{2 \cdot 9 y} : 0

The solutions to the quadratic equation are:

x = \frac{4 y}{9}, x = 0; y \neq = 0

12 x^{2} = 60

x^{2} = 5 x - 1

9 x^{2} + 12 x + 2 = 0

8 x^{2} = 200

x, z = 81 - x^{2} - y

What are the solutions to the equation solvefor x,9x^2y-4xy^2=0 ?
The solutions to the equation solvefor x,9x^2y-4xy^2=0 are x=(4y)/9 ,x=0;\quad y\ne 0
Find the zeros of solvefor x,9x^2y-4xy^2=0
The zeros of solvefor x,9x^2y-4xy^2=0 are x=(4y)/9 ,x=0;\quad y\ne 0