What are the solutions to the equation 6v^2-45=3v ?

The solutions to the equation 6v^2-45=3v are v=3,v=-5/2

Find the zeros of 6v^2-45=3v

The zeros of 6v^2-45=3v are v=3,v=-5/2

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6 v^{2} - 45 = 3 v

v = 3, v = - \frac{5}{2}

Decimal Notation

v = 3, v = - 2.5

Solution steps

6 v^{2} - 45 = 3 v

Move

3 v

to the left side

6 v^{2} - 45 - 3 v = 0

Write in the standard form

a x^{2} + b x + c = 0

6 v^{2} - 3 v - 45 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 45 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 45) = 33

v_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 6}, v_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 6}

v = \frac{- ( - 3 ) + 33}{2 \cdot 6} : 3

v = \frac{- ( - 3 ) - 33}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

v = 3, v = - \frac{5}{2}

x^{2} - 10 x + 20 = - 2

5 t^{2} + 1.3 t - 0.7 = 0

y, (10 - x) y^{2} = x^{3}

x^{2} + 5 x - 2 = 5 x + 2

3 x^{2} + 2 x - 13 = 0

What are the solutions to the equation 6v^2-45=3v ?
The solutions to the equation 6v^2-45=3v are v=3,v=-5/2
Find the zeros of 6v^2-45=3v
The zeros of 6v^2-45=3v are v=3,v=-5/2