What are the solutions to the equation 12^2+5^2=r^2 ?

The solutions to the equation 12^2+5^2=r^2 are r=13,r=-13

Find the zeros of 12^2+5^2=r^2

The zeros of 12^2+5^2=r^2 are r=13,r=-13

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1 2^{2} + 5^{2} = r^{2}

r = 13, r = - 13

Solution steps

1 2^{2} + 5^{2} = r^{2}

Switch sides

r^{2} = 1 2^{2} + 5^{2}

Simplify

1 2^{2} + 5^{2} : 169

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 169, r = - 169

169 = 13

- 169 = - 13

r = 13, r = - 13

18 - 27 x = - 4 x^{2}

2 (x^{2} - 3 x) - x (x - 6) = 25

d^{2} + 3 d - 7 = 0

x, f (x + 1) = - 3 x^{2} - 1

2.6 \cdot 9.8 (3.5 + x) = 0.5 \cdot 512 (x^{2})

What are the solutions to the equation 12^2+5^2=r^2 ?
The solutions to the equation 12^2+5^2=r^2 are r=13,r=-13
Find the zeros of 12^2+5^2=r^2
The zeros of 12^2+5^2=r^2 are r=13,r=-13