What are the solutions to the equation 4x^2+20x+8=0 ?

The solutions to the equation 4x^2+20x+8=0 are x=(-5+sqrt(17))/2 ,x=-(5+sqrt(17))/2

Find the zeros of 4x^2+20x+8=0

The zeros of 4x^2+20x+8=0 are x=(-5+sqrt(17))/2 ,x=-(5+sqrt(17))/2

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4 x^{2} + 20 x + 8 = 0

x = \frac{- 5 + 17}{2}, x = - \frac{5 + 17}{2}

Decimal Notation

x = - 0.43844 \dots, x = - 4.56155 \dots

Solution steps

4 x^{2} + 20 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 8 = 417

x_{1, 2} = \frac{- 20 \pm 4 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 4 17}{2 \cdot 4}, x_{2} = \frac{- 20 - 4 17}{2 \cdot 4}

x = \frac{- 20 + 4 17}{2 \cdot 4} : \frac{- 5 + 17}{2}

x = \frac{- 20 - 4 17}{2 \cdot 4} : - \frac{5 + 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 17}{2}, x = - \frac{5 + 17}{2}

0 = - 27 x^{2} + 1890 x + 9831

(- \frac{5}{3})^{2} + y^{2} = 1

- x^{2} + 4 x - 20

x, x^{2} + y^{2} - 2 x - 6 y + 10 = 0

3 n^{2} + 8 n - 3 = 0

What are the solutions to the equation 4x^2+20x+8=0 ?
The solutions to the equation 4x^2+20x+8=0 are x=(-5+sqrt(17))/2 ,x=-(5+sqrt(17))/2
Find the zeros of 4x^2+20x+8=0
The zeros of 4x^2+20x+8=0 are x=(-5+sqrt(17))/2 ,x=-(5+sqrt(17))/2